(w^2-3w-4)/(5w^2-10w-15)

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Solution for (w^2-3w-4)/(5w^2-10w-15) equation:


D( w )

5*w^2-(10*w)-15 = 0

5*w^2-(10*w)-15 = 0

5*w^2-(10*w)-15 = 0

5*w^2-10*w-15 = 0

5*w^2-10*w-15 = 0

DELTA = (-10)^2-(-15*4*5)

DELTA = 400

DELTA > 0

w = (400^(1/2)+10)/(2*5) or w = (10-400^(1/2))/(2*5)

w = 3 or w = -1

w in (-oo:-1) U (-1:3) U (3:+oo)

(w^2-(3*w)-4)/(5*w^2-(10*w)-15) = 0

(w^2-3*w-4)/(5*w^2-10*w-15) = 0

w^2-3*w-4 = 0

w^2-3*w-4 = 0

DELTA = (-3)^2-(-4*1*4)

DELTA = 25

DELTA > 0

w = (25^(1/2)+3)/(1*2) or w = (3-25^(1/2))/(1*2)

w = 4 or w = -1

(w+1)*(w-4) = 0

5*w^2-10*w-15 = 0

5*(w^2-2*w-3) = 0

w^2-2*w-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

w = (16^(1/2)+2)/(1*2) or w = (2-16^(1/2))/(1*2)

w = 3 or w = -1

5*(w+1)*(w-3) = 0

((w+1)*(w-4))/(5*(w+1)*(w-3)) = 0

( w+1 )

w+1 = 0 // - 1

w = -1

( w-4 )

w-4 = 0 // + 4

w = 4

w in { -1}

w = 4

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